Linear Elastic Lateral Buckling (Including Shear Deformation) and Linear Elastic Lateral Torsional Buckling of Composite Beams - an Analytical Engineering Approach- Juniper Publishers
Juniper Publishers- Journal of Civil Engineering
Abstract
This article outlines a concise and complete
versatile novel analytical framework to quickly and effectively assess
lateral shear (knik) and lateral torsional buckling (kip) of composite
beams build of sections with different lengths. The adjective
"composite” includes dissimilar beam cross-sections (beam profiles) and
distinct beam materials. The major aim is to provide engineers with an
accurate, simple but elegant, practically applicable and analytical beam
buckling tool based on advanced solid theoretical propositions or
background. The justification of the analytical theory is supplied by
demonstration of executed numerical tests (i.e. finite element method),
which affirm the validity of the proposed analytical buckling models
adapted to the considered beam buckling cases.
Keywords: Lateral buckling; Lateral torsional buckling; Composite beam; Analytical formulation; Shear deformation; Linear elasticity
Introduction
Buckling means the loss of stability of an
equilibrium configuration of a structure. Elastic buckling is a state at
which the structure loses its stability and large elastic deflections
will start developing rapidly. It is normally associated with the
minimum eigen value of the perfect structure, i.e. often referred to as
classical buckling [1].
In this article attention is confined to linear elastic composite beam
buckling (especially lateral and lateral torsional buckling phenomena).
An abbreviated and lucid literature survey and comprehensive discussion
about lateral and lateral torsional buckling of structural members is
rendered in the dissertation of Raven [2] and the article of Vander Put [3]. It should be highlighted that the adjective "composite” refers to multiple beam cross-sections and beam materials.
Approximate solution methods are frequently
encountered and used in engineering design practice for tackling beam
buckling problems. In particular, summation theorems (i.e. Foppl
Papkovich theorem) are appropriate and advantageous because of their
robustness, accuracy, easiness and algebraic simplicity [4].
It should be kept in mind that there is similarity or analogy with
parallel and serial analytical approaches of spring systems, electric
systems or hydraulic systems (the so-called analogies).
The key goal of this article is to address
respectively formulate an effective analytical tool for reliable
(engineering) estimation or approximation of the linear elastic lateral
shear buckling force and linear elastic lateral torsional buckling
moment of composite beams made of non-overlapping parts based on the
indicated summation theorem and corresponding well-established
structural elastic stability notions [5]. A succinct but detailed exposition of the previous stated matters and issues is offered in the subsequent sections.
Preliminaries and Requisites
Global Cartesian ( components) and local Cartesian (
components) right-handed coordinate systems are used. The former
identify the composite beam orientation, beam location and beam external
loads, while the latter define attached geometrical (shape and size)
properties of the homogenous beam cross-sections. It is henceforth
assumed that the origin of the local coordinate system is located at the
centroid C of the cross-sectional area. In addition, the initial
(undeformed) geometry of the composite beam is a straight line. The
following beams cross sectional quantities (properties) are employed [6].
![](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.eq1.png)
Where,
A is the cross sectional area,
Iyy , Iyz , Izy and Izz are called second moments of area.
Where, It is the torsion constant.
Note 1: The centroid C is defined as that point of an
area A for which the static moments of area are zero when the origin of
the local xyz coordinate system is chosen there, i.e.
![](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.eq2.png)
The normal centre NC is specified as that point of
the crosssectional area where the resultant of all normal stresses due
to extension has its point of application.
Note 2: In a homogenous (single material) cross-section, the centroid C and normal centre NC coincide.
Note 3: The adopted assumption I yz = Izy = 0 implies that the selected beam cross section has at least two lines of symmetry.
Note 4: I yy and Izz are commonly indicated as the moments of inertia and I yz , I zy are known as the product of inertia. The Equations (1) have been applied to the cross-sections in Figure 1. The results are Shown below.
![Click here to view Large Figure 1](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.G001.png)
![](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.eq3.png)
![](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.eq4.png)
Linear elastic lateral buckling (including shear deformation) (knik)
Model geometry
The typical model geometry is depicted in Figure 2. The following mechanical boundary (displacement and load) conditions are implemented (prescribed).
![Click here to view Large Figure 2](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.G002.png)
Boundary 1: uX = O, uY = O, uz = O , Fx = l (applied at centroid)
Boundary 2: uY = 0, uZ = 0 , FX = -1 (applied at centroid)
Note 1: A set of balanced forces is obligatory in
order to preserve equilibrium of the composite beam in the analytical
model configuration.
Note 2: The prescribed boundary displacement
constraints prevent rigid body motions (circumvent singularities in the
numerical (finite element) solution process).
Analytical model
The composite beam with length L is made of segments i with corresponding length Li (Figure 3) and each segment (section) i has the accompanying attributes Young's modulus Ei shear modulus Gi , shear deformation coefficient ksi [7,8] crosssection area Ai and second moment of area
Ii Furthermore, the cross-section of each segment i fulfils the condition Iyyi < Izzi , which implies that Ii=Iyyi Consequently, the following relation holds.
![Click here to view Large Figure 3](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.G003.png)
![](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.eq5.png)
The engineering estimate of the buckling length Ltmci segment i is given by the expression
Lbuci = kbucLi (3)
Where,
Kbuc Is the buckling length factor, which is identical for each segment in the particular composite beam arrangement.
![](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.eq6.png)
Kbc Is the buckling length factor of the
composite beam, dependent on the mechanical boundary conditions
(supports). In this specific case of a composite beam with span L and
supported by two hinges at the edges k bc = 1.
It is emphasized that the buckling length of the
composite beam depends only on the boundary conditions and thus not on
cross-sectional properties. Substitution of Equation 4 into Equation 3
produces the following identity.
![](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.eq7.png)
Subsequently, the linear elastic lateral shear buckling force Fbuci of segment i is universally elaborated as shown in Equation 6a. Note that shear deformation is also incorporated, see [5], (Timoshenko 1985).
![](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.eq8.png)
Fbuc Is the linear elastic lateral shear buckling force of segment i,
Fbuclaterali Is the linear elastic lateral buckling force of segment i,
![](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.eq9.png)
Recalling from literature that the Foppl-Papkovich
theorem (Tarnai 1995) is valid for this case, the following lateral
shear buckling system force equation is stated in general format.
![](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.eq10.png)
Fbucsys Is the linear elastic lateral shear buckling force of the composite beam (also denoted as system), n Is the total number of considered segments.
The aforementioned formulae devise the complete linear elastic lateral shear buckling analytical model.
Numerical verification (case studies) knik
Three case studies (KNIK 1, KNIK 2 and KNIK 3) are
conducted and concisely presented in order to examine the validity and
soundness of the proposed analytical approach by comparison with
numerical results obtained by the finite element method [9,10].
Case study KNIK 1-1
Case KNIK 1-1 considers a wooden beam of one segment (Figure 4).
The properties are L = 3000 mm, L1 = 3000 mm, Kbuc = 1,Kbc = 1,FX=±N,
![](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.eq0.png)
The obtained results are Fbucsysnumerical =14214N and Fbucsysnumerical = 14221N (Figure 5).
![](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.eq.png)
![Click here to view Large Figure 4](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.G004.png)
Case study KNIK 1-2
Case KNIK 1-2 considers a composite wooden beam of two segments (Figure 6).
![](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.eq12.png)
![](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.eq13.png)
The results are Fbucsysamlytical =I673N, Fbucsysnumerical= I443N
(Figure 7). The deviation is -13, 74 %.
Case study KNIK 1-3
![Click here to view Large Figure 6](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.G006.png)
Case KNIK 1-3 considers a composite wooden beam of three segments (Figure 8).
The properties are L = 3000 mm, L1 = 1000 mm, L2 = 1000 mm, L3 = 1000 mm,
![](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.eq14.png)
The results are Fbucsysanalytical =156 N and Fbucsysnumerical = 161 N
(Figure 9). The deviation is +3, 11 %.
![Click here to view Large Figure 8](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.G008.png)
Case Study KNIK 2-1
Case KNIK 2-1 considers a steel beam of one segment (Figure 10).
The properties are L = 3000 mm, L1 = 3000 mm, Kbuc = 1,Kbc = 1,FX=±N,
![](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.eq18.png)
The obtained results are Fbucsysnumerical =328263N and Fbucsysnumerical = 326493N (Figure 11).
![Click here to view Large Figure 10](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.G0010.png)
The deviation is -0,539 %.
Case Study KNIK 2-2
Case KNIK 2-2 considers a composite steel beam of two segments (Figure 12).
The properties are L = 3000 mm, L1 = 1500 mm, L2 = 1500 mm, kbuc = 2, kbC = 1, FX = ±1 N,
![](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.eq19.png)
The results are Fbucsysnumerical = 157757N and Fbucsysnumerical=
147745N (Figure 13) the deviation is -6,346%.
![Click here to view Large Figure 12](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.G0012.png)
Case Study KNIK 2-3
Case KNIK 2-3 considers a composite steel beam of 3 segments (Figure 14).
The properties are L = 3000 mm, L1 = 1000 mm, L2 = 1000 mm, L3 = 1000 mm,
![](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.eq20.png)
The results are Fbucsysanalytical = 47024N and fbucsysnumerical= 48983N (Figure 15). The deviation is +4,165 %.
![Click here to view Large Figure 14](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.G0014.png)
![Click here to view Large Figure 16](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.G0016.png)
Case Study KNIK 3-3
Case KNIK 3-3 considers a composite steel-wood beam of three segments (Figure 16).
The properties are L = 3000 mm, L1 = 1000 mm, L2 = 1000mm,L3 = 1000 mm,
![](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.eq21.png)
The results are = 166 N and = 171 N (Figure 17). The deviation is +3,012 %.
Linear elastic lateral torsional buckling (kip)
Model geometry
The governing model geometry is shown in Figure 18. The following mechanical boundary (displacement and load) conditions are implemented (prescribed).
Boundary 1: ux = 0 uy = 0 uz = 0 , φx = 0, Mz = -1 (applied at centroid).
Boundary 2: uy = 0 uz = 0 , φx = 0,
Mz = +1 (applied at centroid).
![Click here to view Large Figure 1](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.G0018.png)
Analytical model
The model for lateral torsional buckling is mostly
identical to the models for lateral buckling (Section 7.2). Not used in
lateral torsional buckling is the shear deformation coefficient ks1. Extra is the is the torsional constant Iti,.
The cross-sectional warping stiffness of segment i is assumed to be
negligible. The engineering estimate of the buckling length Lbuci of segment i is
Lbuci = kbucLi (8)
Where,
kbuc Is the buckling length factor. Which, is the same for each segment in the specific composite beam configuration
![](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.eq15.png)
kbuc Is the buckling length factor
of the composite beam, dependent on the mechanical boundary conditions
(support). In this specific case of a composite beam with span L and
supported by two forks at the edges:
kbc = 1
It is underlined that the buckling length of the
composite beam is only dependent on the boundary conditions and hence
not on cross-sectional properties. Substitution of Equation 9 in
Equation 8 produces the following identity.
Lbuci = kbucLi (10)
Taking into account the previous settled propositions, the linear elastic lateral torsional buckling moment Mbuci of segment i is
![](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.eq16.png)
The Föppl-Papkovich theorem (Tarnai 1995) is apt for
this case. The following lateral torsional buckling system moment
equation is written in universal layout.
![](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.eq17.png)
Mbucsys Is the linear elastic lateral torsional buckling moment of the composite beam (also symbolized as system).
n is the total number of segments.
The aforesaid procedure details the full linear elastic lateral torsional buckling analytical model.
Numerical verification (case studies) kip
Three case studies (KIP 1, KIP 2 and KIP 3) are
consecutively undertaken and compendiously offered in order to inspect
the legality or reliability of the analytical approach by judgment of
numerical results.
Case study KIP 1-1
Case KIP 1-1 considers a wooden beam of one segment (Figure 19).
The properties are L = 3000 mm, L1 = 3000 mm, kbuc = 1, kbc =±1 Nmm,
![](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.eq22.png)
The results are M buaysanaiytcai = 0,149-108 Nmm and M buaysanaiytcai= 0,149-108 Nmm (Figure 20).
![](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.eq23.png)
![Click here to view Large Figure 19](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.G0019.png)
Case study KIP 1-2
Case KIP 1-2 considers a composite wooden beam of two segments (Figure 21).
The properties are L = 3000 mm, L1 = 1500 mm, L2 = 1500 mm, kbuc = 1, kbc = 1, MZ = ±1 Nmm,
![](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.eq24.png)
The results are M buaysanaiytcai = 0,175-107NmmM buaysanaiytcai and =0,176-107Nmm (Figure 22).
![Click here to view Large Figure 20](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.G0020.png)
![Click here to view Large Figure 23](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.G0023.png)
The deviation is +0, 57%.
Case study KIP 1-3
Case KIP 2-3 considers a composite wooden beam of three segments (Figure 23).
The properties are L = 3000 mm, L1 = 1000 mm, L2 = 1000 mm, L3 = 1000 mm, kbuc =1, kbc = 1, Mz = ±1 Nmm,
![](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.eq25.png)
![](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.eq26.png)
The results are M bucsysanalytical = 163701 Nmm and Mbucsysnumerical = 164801 Nmm (Figure 24).
The deviation is +0, 67 %.
Case study KIP 2-1
Case KIP 2-1 considers a steel beam of one segment (Figure
25).
The properties are L = 3000 mm, L1 = 3000 mm, kbuc = 1, kbc = 1, —z = ±1 Nmm,
![](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.eq27.png)
The obtained results are M bucsysanalytical = 37, 48-106 Nmm and M bucsysanalytical = 37,5-106 Nmm (Figure 26).
![Click here to view Large Figure 25](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.G0025.png)
The deviation is +0,053 %.
Case study KIP 2-2
Case KIP 2-2 considers a composite steel beam of two segments (Figure 27).
The properties are L = 3000 mm, L1 = 1500 mm, L2 = 1500 mm, kbuc = 1, kbc = 1, MZ = ±1 Nmm,
![](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.eq28.png)
The results are M bucsysanalytical = 19, 55-106 Nmm and M bucsysanalytical= 19, 2106 Nmm (Figure 28).
![Click here to view Large Figure 27](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.G0027.png)
![Click here to view Large Figure 29](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.G0029.png)
The deviation is -1, 79 %.
Case study KIP 2-3
Case KIP 2-3 considers a composite steel beam of three segments (Figure 29).
The properties are L = 3000 mm, L1 = 1000 mm, L2 = 1000 mm, L3 = 1000 mm, kbuc = 1, Kc = 1, MZ = ±1 Nmm,
![](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.eq29.png)
The results are = 6, 91-106 Nmm are = 6, 68-106 Nmm (Figure 30).
The deviation is -3,328 %.
Case study KIP 3-3
Case KIP 3-3 considers a composite steel-wood beam of three segments (Figure 31).
The properties are L = 3000 mm, L1 = 1000 mm, L2 = 1000 mm, L3 = 1000 mm, kbuc = 1,
kbuc = 1, MZ = ±1 Nmm,
![](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.eq30.png)
The results are = 174324 Nmm and = 175756 Nmm (Figure
32).
The deviation is +0,821 %.
![Click here to view Large Figure 31](https://juniperpublishers.com/cerj/images/CERJ.MS.ID.555604.G0031.png)
Conclusion
Numerical evaluation confirms the correctness of the
presented linear elastic lateral shear and lateral torsional buckling
analytical models. The deviations between the analytical and numerical
approach are rather small and reveal clearly the ability to yield
realistic outcomes. The supplied analytical linear elastic buckling
models produce accurate and reliable values, which can be classified as
suitable for engineering design purposes. Needless to cite that the
analytical approach should always be cautiously applied and the results
ought to be methodically checked by the responsible structural engineer.
A salient observation is that the presented tactic could also be
invoked for linear elastic buckling assessment of castellated and
cellular (steel) beams. However, this assertion has not yet been
verified and is thus speculative. Insertion of plasticity is
straightforward however treatment of this topic is beyond the scope of
this article.
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